When the 'bootstrap.sh' script is run with the '-f' option to fetch first before bootstrapping, then invoked a second time to start bootstrap, the script will report that the system has already been bootstrapped. It will then quit without bootstrapping (even if I "press enter to continue"). It appears that the transparent resume process in the 'bootstrap.sh' is setting the BOOTSTRAP_STAGE variable found in /var/run/bootstrap-progress to a value of '6' during the fetchonly run of the bootstrap script. Setting BOOTSTRAP_STAGE=0 allowed the system to bootstrap sucessfully and proceed through to stage2. I was attempting a stage 1 install using Knoppix as per the Alternate Installation Methods instructions. The stage used for installation was: stage1-x86-2004.3.tar.bz2 dated 13-Nov-2004. Reproducible: Always Steps to Reproduce: 1. Proceed through installation instructions for x86 stage1 to step 6.c. 2. execute scripts/bootstrap.sh -f 3. execute scripts/bootstrap.sh Actual Results: script reports: "System has been bootstrapped already!" "If you re-bootstrap the system you must compelete the entire bootstrap process" "Otherwise you will have a broken system." "Press enter to continue or CTRL+C to abort..." Pressing enter does not cause the system to bootstrap. Expected Results: Should have begun and finished bootstrap process using the files downloaded in the 'bootstrap.sh -f' step.
*** This bug has been marked as a duplicate of 72573 ***
