Example command in "Code listing 6.1" reads: "# dd if=/dev/zero of=/dev/hdxy bs=1K" yet if it is to do as the instructions say and only wipe the first 1024 sectors of the HD the command should be: "# dd if=/dev/zero of=/dev/hdxy bs=1K count=1" As written the command will wipe the entire hard drive. This shouldn't be critical because the user would only zero out the partition table of a drive on which nothing they wanted to keep existed. However, it still will take much longer due to all the extra work to fill the drive.
Thanks for the heads up, fixed in cvs. Cheers, //zhen