#LyX 1.2 created this file. For more info see http://www.lyx.org/ \lyxformat 220 \textclass article \begin_preamble \usepackage{times} \usepackage[T1]{fontenc} \usepackage[latin1]{inputenc} \pagestyle{empty} \usepackage{babel} \makeatletter \setlength{\parindent}{0in} \setlength{\parskip}{.25in} \setlength{\textheight}{9.3in} \setlength{\topmargin}{-.6in} \textwidth=6.5in \addtolength{\oddsidemargin}{-.85in} \makeatother \end_preamble \options english \language english \inputencoding latin1 \fontscheme times \graphics default \paperfontsize 10 \spacing single \papersize letterpaper \paperpackage a4 \use_geometry 0 \use_amsmath 0 \use_natbib 0 \use_numerical_citations 0 \paperorientation portrait \secnumdepth 3 \tocdepth 3 \paragraph_separation indent \defskip medskip \quotes_language english \quotes_times 2 \papercolumns 1 \papersides 1 \paperpagestyle default \layout Standard Problem Set #3 \hfill Chem 332 --- Spring 2003 \newline \series bold Due: 4 March 2003 \series default \hfill Grant Goodyear \newline \begin_inset ERT status Collapsed \layout Standard \backslash rule{6.5in}{.0625in} \end_inset \layout Enumerate A general property of solutions of the time-independent Schrodinger equation is that wavefunctions must be \emph on orthonormal \emph default : \begin_inset Formula \[ \int d\vec{r}\: \psi _{n}^{*}(\vec{r})\psi _{m}(\vec{r})=\left\{ \begin{array}{cc} 1, & n=m\\ 0, & n\neq m\end{array}\right..\] \end_inset Let's introduce a bit of notational shorthand: \begin_inset Formula \[ \delta _{nm}\equiv \left\{ \begin{array}{cc} 1, & n=m\\ 0, & n\neq m\end{array}\right.,\] \end_inset where \begin_inset Formula $\delta _{nm}$ \end_inset is called the \begin_inset Quotes eld \end_inset Kronecker delta \begin_inset Quotes erd \end_inset . Explicitly writing out the integrals is also a bit of a pain, so \begin_inset Quotes eld \end_inset bra \begin_inset Quotes erd \end_inset -c- \begin_inset Quotes erd \end_inset ket \begin_inset Quotes erd \end_inset notation was developed: \begin_inset Formula \[ \equiv \int d\vec{r}\: \psi _{n}^{*}(\vec{r})\psi _{m}(\vec{r}),\] \end_inset and \begin_inset Formula \[ \equiv \int d\vec{r}\: \psi _{n}^{*}(\vec{r})\hat{o}\psi _{m}(\vec{r}),\] \end_inset where \begin_inset Formula $$ \end_inset and \begin_inset Formula $$ \end_inset are both referred to as \begin_inset Quotes eld \end_inset matrix elements \begin_inset Quotes erd \end_inset . Show that the particle-in-a-box wavefunctions satisfy \begin_inset Formula $=\delta _{nm}$ \end_inset . \layout Enumerate If an electron confined in a box were not quantum mechanical, it would have an equal probability for being anywhere in the box. Assuming a box of length L, \begin_deeper \layout Enumerate What would P(x), the probability density, be in this classical case? \layout Enumerate What would \begin_inset Formula $\sigma _{x}$ \end_inset (the root-mean-square fluctuation in position) be? \layout Enumerate Compute what the same root-mean-square fluctuation in position would be if the electron really were quantum mechanical but the electron happened to be in a state with an infinitely large quantum number n. What is the relationship with the answer you found for part (b)? Why? \end_deeper \layout Enumerate Retinal, the molecule responsible for human and animal vision, has 6 conjugated double bonds (the backbone is C=C-C=C-C=C-C=C-C=C-C=C). Retinal, of course, absorbs visible light. Using a particle-in-a-box model, how many cojugated double bonds would be needed to see infrared light ( \begin_inset Formula $\lambda \geq 800$ \end_inset nm)? \layout Enumerate S&A, probs. 9.12, 9.14, 9.15 \layout Enumerate The experimental vibrational frequency for an \begin_inset Formula $\mathrm{H}_{2}$ \end_inset molecule is \begin_inset Formula $\omega /2\pi c=4395.2\: \mathrm{cm}^{-1}$ \end_inset . Use this experimental result to predict the vibrational frequency of \begin_inset Formula $\mathrm{D}_{2}$ \end_inset . (Hint: when you change isotopes from H to D, what should change and what should stay the same?) \layout Enumerate The rate at which a molecule absorbs light is determined by the value of the matrix element \begin_inset Formula $$ \end_inset , where \begin_inset Formula $i$ \end_inset is the initial quantum state of the molecule, \begin_inset Formula $f$ \end_inset is the final quantum state of the molecule (after the light is absorbed), and \begin_inset Formula $\hat{\mu }$ \end_inset is the dipole operator. For practical purposes, the dipole operator is a constant times the position operator: \begin_inset Formula $\hat{\mu }=a\hat{x}$ \end_inset . \begin_deeper \layout Enumerate Before going further, we need a couple of useful mathematical relationships. Define \emph on even \emph default and \emph on odd \emph default functions according to \begin_inset Formula $f_{\mathrm{even}}(-x)=f_{\mathrm{even}}(x)$ \end_inset and \begin_inset Formula $f_{\mathrm{odd}}(-x)=-f_{\mathrm{odd}}(x)$ \end_inset . Prove the \begin_inset Quotes eld \end_inset symmetry results \begin_inset Quotes erd \end_inset \begin_inset Formula $\int _{-a}^{a}f_{\mathrm{odd}}(x)=0$ \end_inset and \begin_inset Formula $\int _{-a}^{a}f_{\mathrm{even}}(x)=2\int _{0}^{a}f_{\mathrm{even}}$ \end_inset . Also prove that \begin_inset Formula $f_{\mathrm{even}}(x)f_{\mathrm{odd}}(x)$ \end_inset (the product) is an odd function, while \begin_inset Formula $f_{\mathrm{even}}(x)f_{\mathrm{even}}(x)$ \end_inset and \begin_inset Formula $f_{\mathrm{odd}}(x)f_{\mathrm{odd}}(x)$ \end_inset are even functions. \layout Enumerate Assume that molecular vibration can be modeled with a simple harmonic oscillator. In that case symmetry considerations would tell us that light could only take a molecule starting in the ground state (n=0) to states n=1, 3, 5, \begin_inset Formula $\cdots $ \end_inset . Why? If symmetry were the only consideration, what frequencies \begin_inset Formula $\upsilon $ \end_inset could be absorbed? \layout Enumerate In fact, when you do IR spectroscopy of vibrating molecules you don't see all of those frequencies. We can actually understand this observation using the harmonic oscillator model because one can use the special properties of harmonic oscillator wave functions to show that all of the matrix elements of x which connect to the ground state vanish, except for the one that connects to the first excited state: \begin_inset Formula $=0$ \end_inset unless f=1. Within the harmonic approximation what frequencies of light should be absorbed? \layout Enumerate Let's prove this special property of simple-harmonic-oscillator matrix elements. Show that with the simple-harmonic-oscillator wave functions \begin_inset Formula $x\psi _{0}(x)=C\psi _{1}(x)$ \end_inset for some constant \begin_inset Formula $C$ \end_inset . Determine \begin_inset Formula $C$ \end_inset . \layout Enumerate Write out \begin_inset Formula $$ \end_inset as an integral and substitute in your result from part (c). What you have written immediately tells you that only the \begin_inset Formula $f=1$ \end_inset matrix element has a non-zero value. Why? What's the value of this matrix element? \end_deeper \layout Enumerate Compute \begin_inset Formula $\sigma _{x}\sigma _{p}$ \end_inset for the harmonic oscillator ground state. The harmonic oscillator ground state is often called a \begin_inset Quotes eld \end_inset minimum uncertainty \begin_inset Quotes erd \end_inset wavepacket. Why \begin_inset Quotes eld \end_inset minimum uncertainty \begin_inset Quotes erd \end_inset ? \layout Enumerate Of the following molecules: \begin_inset Formula $\mathrm{H}_{2}$ \end_inset , HCl, \begin_inset Formula $\mathrm{CH}_{4}$ \end_inset , \begin_inset Formula $\mathrm{CH}_{3}\mathrm{Cl}$ \end_inset , \begin_inset Formula $\mathrm{H}_{2}\mathrm{O}$ \end_inset , and \begin_inset Formula $\mathrm{CO}_{2}$ \end_inset , which have rotations that will show up in microwave spectroscopy? Which have IR active vibrations? Raman active vibrations? \layout Enumerate S&A, probs. 9.29, 9.36. \layout Enumerate A space probe was designed to look for signs of CO in the atmosphere of Saturn. It was decided to employ a microwave technique from an orbiting satellite. Given the bond length of CO is 112.82 pm, at what wavenumbers do the first four transitions of \begin_inset Formula $^{12}\mathrm{C}^{16}\mathrm{O}$ \end_inset lie? What resolution is needed if it was desired to distinguish the 0 \begin_inset Formula $\rightarrow $ \end_inset 1 line in the \begin_inset Formula $^{12}\mathrm{C}^{16}\mathrm{O}$ \end_inset spectrum from that of \begin_inset Formula $^{13}\mathrm{C}^{16}\mathrm{O}$ \end_inset in order to examine the relative abundances of the two carbon isotopes? \the_end